(2x+3)(x^2-1)=0

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Solution for (2x+3)(x^2-1)=0 equation: 


Simplifying
(2x + 3)(x2 + -1) = 0

Reorder the terms:
(3 + 2x)(x2 + -1) = 0

Reorder the terms:
(3 + 2x)(-1 + x2) = 0

Multiply (3 + 2x) * (-1 + x2)
(3(-1 + x2) + 2x * (-1 + x2)) = 0
((-1 * 3 + x2 * 3) + 2x * (-1 + x2)) = 0
((-3 + 3x2) + 2x * (-1 + x2)) = 0
(-3 + 3x2 + (-1 * 2x + x2 * 2x)) = 0
(-3 + 3x2 + (-2x + 2x3)) = 0

Reorder the terms:
(-3 + -2x + 3x2 + 2x3) = 0
(-3 + -2x + 3x2 + 2x3) = 0

Solving
-3 + -2x + 3x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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